Chi-square Test Example Problems With Answers Ppt -

The die is fair (no evidence of bias). Slide 7: Problem 2 – Goodness-of-Fit (Traffic Fatalities) Scenario: A safety officer claims that fatal accidents are equally likely on each weekday. Observed data: Mon=25, Tue=18, Wed=20, Thu=22, Fri=35 (Total = 120) Test at α = 0.01.

Slide 14: Problem 4 – Expected & Chi-Square (Summary) Show only the final calculated table (too large for all cells): chi-square test example problems with answers ppt

Visual suggestion: Include a clustered bar chart comparing male/female preferences. Scenario: | | Regular | Occasional | Never | Total | |-----------|---------|------------|-------|-------| | Graduate | 40 | 30 | 10 | 80 | | Some College | 30 | 40 | 20 | 90 | | High School | 20 | 25 | 35 | 80 | | Total | 90 | 95 | 65 | 250 | The die is fair (no evidence of bias)

= ( 120 / 5 = 24 ) Slide 8: Problem 2 – Quick Calculation | Day | O | E | (O-E)²/E | |-----|---|----|----------| | Mon |25 |24 | 1/24 = 0.0417 | | Tue |18 |24 | 36/24 = 1.5 | | Wed |20 |24 | 16/24 = 0.6667 | | Thu |22 |24 | 4/24 = 0.1667 | | Fri |35 |24 | 121/24 = 5.0417 | Slide 14: Problem 4 – Expected & Chi-Square

[ \chi^2 = \sum \frac(O - E)^2E ] Slide 4: Problem 1 – Goodness-of-Fit (Fair Die?) Scenario: A die is rolled 60 times. Observed frequencies: 1→8, 2→12, 3→10, 4→9, 5→11, 6→10 Question: Is the die fair? (α = 0.05)

Gender and product preference are dependent (significant association).

( E = 60 \times \frac16 = 10 ) for each face. Slide 5: Problem 1 – Calculation Table | Face | O | E | (O-E) | (O-E)² | (O-E)²/E | |------|---|---|-------|--------|----------| | 1 | 8 | 10| -2 | 4 | 0.4 | | 2 |12 | 10| 2 | 4 | 0.4 | | 3 |10 | 10| 0 | 0 | 0.0 | | 4 | 9 | 10| -1 | 1 | 0.1 | | 5 |11 | 10| 1 | 1 | 0.1 | | 6 |10 | 10| 0 | 0 | 0.0 |